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0.5kg of water at 10⁰C is completely converted to ice at 0⁰C by…

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PHYSICS

0.5kg of water at 10⁰C is completely converted to ice at 0⁰C by extracting (88000) of heat from it. If the specific heat capacity of water is 4200jkg⁻¹ ⁰C⁻¹. Calculate the specific latent heat of fusion of ice.

A. 9.0 kjkg⁻¹

B. 84.0 kjkg⁻¹

C. 134.0 kjkg⁻¹

D. 168.0 kjkg⁻¹

QUICK ANSWER…

C

DETAILS…

Total heat lost = MCΔT + ML

Or Heat lost = M(CΔT + L)

Where:

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Heat lost = 88000j

M = mass of water = 0.5kg

C = specific heat capacity of water = 4200jkg⁻¹ ⁰C⁻¹

ΔT = change in temperature = (10 – 0) = 10⁰C

L = latent heat of fusion of ice =?

Substituting these, we have:

88000 = 0.5(4200×10 + L)

(4200×10 + L) = 88000/0.5

42000 + L = 176000

L = 176000 – 42000

L = 134000J/Kg or 134Kj/Kg

Now for the right answer to the above question:

  1. Option A is incorrect.
  2. Option B is incorrect.
  3. C is correct.
  4. D is not the correct answer.

KEY-POINTS…

You may please note these/this:

  • Total heat lost by the water = MCΔT + ML.
  •  Taking out heat from the water enabled the state change.

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/ culled from 2021 JAMB-UTME PHYSICS question 8 /

1 Answers

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    Heat Change = = MCΔT + ML

    Admin - Mar 22, 2022 | Reply


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