0.5kg of water at 10⁰C is completely converted to ice at 0⁰C by…
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0.5kg of water at 10⁰C is completely converted to ice at 0⁰C by extracting (88000) of heat from it. If the specific heat capacity of water is 4200jkg⁻¹ ⁰C⁻¹. Calculate the specific latent heat of fusion of ice.
A. 9.0 kjkg⁻¹
B. 84.0 kjkg⁻¹
C. 134.0 kjkg⁻¹
D. 168.0 kjkg⁻¹
Total heat lost = MCΔT + ML
Or Heat lost = M(CΔT + L)
Heat lost = 88000j
M = mass of water = 0.5kg
C = specific heat capacity of water = 4200jkg⁻¹ ⁰C⁻¹
ΔT = change in temperature = (10 – 0) = 10⁰C
L = latent heat of fusion of ice =?
Substituting these, we have:
88000 = 0.5(4200×10 + L)
(4200×10 + L) = 88000/0.5
42000 + L = 176000
L = 176000 – 42000
L = 134000J/Kg or 134Kj/Kg
Now for the right answer to the above question:
- Option A is incorrect.
- Option B is incorrect.
- C is correct.
- D is not the correct answer.
You may please note these/this:
- Total heat lost by the water = MCΔT + ML.
- Taking out heat from the water enabled the state change.
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/ culled from 2021 JAMB-UTME PHYSICS question 8 /