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**A bag contains 4 white balls and 6 red balls. Two balls are taken from the bag without replacement. What is the probability that they are both red?**

**A.**** ****3/5**

**B.**** 1/5**

**C.**** ****2/15**

**D.**** ****1/3**

**QUICK ANSWER…**

**D**

**DETAILS…**

**We’re going to determine the probability for each ball picked, and then multiply both to find the probability that they are both red.**

**For the first pick:**

**Probability of picking red = 6/(6 + 4) = 6/10 = 3/5**

**For the second pick:**

**Recall that there was no replacement, hence, this implies that there will remain 4 white balls and 5 red balls.**

**So, probability of picking a second red ball = 5/(5 + 4) = 5/9**

**Finally, the probability that both picks are red = probability of first pick ****×**** probability of second pick = 3/5 ****×**** 5/9 = 3/9 = 1/3**

**Now for the right answer to the above question:**

**Option A is incorrect.****Option B is incorrect.****C is not correct.****D is the correct answer.**

**KEY-POINTS…**

**You may please note these/this:**

**There was no replacement, this means after the first pick, the number of red balls in the bag reduced by one.****If you love our answers, you can login to comment and say hi to us at the comment section…**

**To raise new related question****s, c****lick the ASK A QUESTION BOTTON down this page…**

**/ culled from 2020 JAMB-UTME mathematics past question 26 /**