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# A pentagon has four of its angles equal, If the size of the fifth angle is 60…

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**A pentagon has four of its angles equal, If the size of the fifth angle is 60, find the size of each of the four equal angles**

**A.**** ****108⁰**

**B.**** 120⁰**

**C.**** ****150⁰**

**D.**** 60⁰**

**QUICK ANSWER…**

**B**

**DETAILS…**

**Let each of the four equal angles of the pentagon be represented by x, hence, all the angles will be:**

**x, x, x, x, and 60**

**now recall that the sum of all the internal angles of a polygon = 180(n – 2), where n is the number of angles which is 5 in this case. This implies:**

**x + x + x + x + 60 = 180(5 – 2)**

**4x + 60 = 180(3)**

**4x + 60 = 540**

**4x = 540 – 60**

**4x = 480**

**x = 480/4 = 120****⁰**

**Now for the right answer to the above question:**

**Option A is incorrect.****Option B is correct.****C is not correct.****D is not the correct answer.**

**KEY-POINTS…**

**You may please note these/this:**

**Sum of all the interior angles of a polygon = 180(n – 2)****Sum of all the exterior angles of a polygon = 360****If you love our answers, you can login to comment and say hi to us at the comment section…**

**To raise new related question****s, c****lick the ASK A QUESTION BOTTON down this page…**

**/ culled from 2020 JAMB-UTME mathematics past question 19 /**

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