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**A straight wire 15cm long, carrying a current of 6.0A is in a uniform field of 0.40T. what is the force on the wire when it is at right angle to the field?**

- A.
**0.46N** - B.
**0.35N** - C.
**0.36N** - D.
**0.24N**

**QUICK ANSWER…**

**C**

**DETAILS…**

**The force experienced by a current carrying conductor placed in a magnetic field can be calculated using the following formula:**

**F = BILsinx**

**Where F = force experienced by the conductor = ?**

**B = magnetic field = 0.4T**

**I = current = 6A**

**L = length of the conductor = 15cm = 15/100 = 0.15m**

**x = angle between the field direction and the current direction = right angled = 90degrees.**

**Substituting these values, we have:**

**F = BILsinx**

**F = 0.4 X 6 X 0.15 X sin90**

**F = 0.4 X 6 X 0.15 X 1 = 0.36N**

**Now for the right answer to the above question:**

**Option A is incorrect.****Option B is incorrect.****C is correct.****D is not the correct answer.**

**KEY-POINTS…**

**You may please note these/this:**

**The force experienced by a current carrying conductor placed in a magnetic field can be calculated with this equation: F = BILsinx.**

**Use the questions and answer section to correct, express, and contribute your views.**

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**/culled from 2019 JAMB-UTME physics question 19/**