A straight wire 15cm long, carrying a current of 6.0A is in a uniform field of 0.40T. what is the force on the wire when it is at right angle to the field?
- A. 0.46N
- B. 0.35N
- C. 0.36N
- D. 0.24N
The force experienced by a current carrying conductor placed in a magnetic field can be calculated using the following formula:
F = BILsinx
Where F = force experienced by the conductor = ?
B = magnetic field = 0.4T
I = current = 6A
L = length of the conductor = 15cm = 15/100 = 0.15m
x = angle between the field direction and the current direction = right angled = 90degrees.
Substituting these values, we have:
F = BILsinx
F = 0.4 X 6 X 0.15 X sin90
F = 0.4 X 6 X 0.15 X 1 = 0.36N
Now for the right answer to the above question:
- Option A is incorrect.
- Option B is incorrect.
- C is correct.
- D is not the correct answer.
You may please note these/this:
- The force experienced by a current carrying conductor placed in a magnetic field can be calculated with this equation: F = BILsinx.
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/culled from 2019 JAMB-UTME physics question 19/