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**A train has an initial velocity of 44m/s and an acceleration of -4ms-2. Calculate its velocity after 10 seconds**

- A.
**10m/s** - B.
**6m/s** - C.
**8m/s** - D.
**4m/s**

**QUICK ANSWER…**

**D**

**DETAILS…**

**Data given:**

**Initial velocity (u) = 44m/s**

**Acceleration of train (a) = -4ms-2**

**Final velocity (v) = ?**

**Time of travel (t) = 10 seconds.**

**According the first law of motion,**

**v = u + at**

**v = 44 + (-4)10**

**v = 44 – 40 = 4m/s**

**Now for the right answer to the above question:**

**Option A is incorrect.****Option B is incorrect.****C is incorrect.****D is the correct answer.**

**HELPFUL TIPS…**

**You may please note these/this:**

**Be careful, acceleration is a vector quantity, and so its direction which is implied by the negative sigh, is very important.**

**Use the questions and answer section to correct, express, and contribute your views.**

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**/culled from 2019 JAMB-UTME physics question 7/**