3 Answers

Calculate the mass of ice that would melt when 2kg of copper is…

Posted by: 215 views , ,
PHYSICS

Calculate the mass of ice that would melt when 2kg of copper is quickly transferred from boiling water to a block of ice without heat loss.

(specific heat capacity of copper = 400Jkg⁻¹k⁻¹, latent heat of fusion of ice = 3.3 x 10⁵Jkg⁻¹)

A. 8/33kg

B. 3.3/80kg

C. 80/33kg

D. 3.3/8kg

QUICK ANSWER…

A

DETAILS…

the mass of ice that would melt when 2kg of copper is quickly transferred from boiling water to a block of ice without heat loss is 8/33 kg. let me explain…

heat lost by copper = heat gained by ice

mcΔT = ML

where:

m = mass of copper = 2kg

c = specific heat capacity of copper = 400Jkg⁻¹k⁻¹

ΔT = change in temperature = temperature of boiling water – temperature of ice = 100⁰C – 0⁰C = 373k – 273k = 100k

RELATED!  A piece of substance of specific heat capacity 450Jkg⁻¹k⁻¹ falls...

M = mass of ice =?

L = latent heat of fusion of ice = 3.3 x 10⁵Jkg⁻¹

mcΔT = ML

therefore,

M = mcΔT/L

M = (2 × 400 × 100)/(3.3 × 10⁵)

M = 80000/(3.3 × 10⁵)

M = (8 × 10⁴)/(3.3 × 10⁵), or

M = (8 × 10⁴)/(33 × 10⁴)

M = (8 × 10⁴)/(33 × 10⁴)

M = 8/33kg

Now for the right answer to the above question:

  1. Option A is correct.
  2. Option B is incorrect.
  3. C is incorrect.
  4. D is not the correct answer.

KEY-POINTS…

You may please note these/this:

  • Heat lost by hot copper = heat gained by ice.
  • Or, mcΔT = ML.
  • In reality, this formula only assumes that all the heat is used to melt the ice only, no heat will be lost to some already melted water in the process or the container.

If you love our answers, you can simply join our community and also provide answers like this, fellow learners like you will appreciate it.

/ culled from 2021 JAMB-UTME PHYSICS question 32 /

3 Answers

  1. 0 Votes Thumb up 0 Votes Thumb down 0 Votes

    In reality, this formula only assumes that all the heat is used to melt the ice only, no heat will be lost to some already melted water in the process or the container.

    Admin - Mar 25, 2022 | Reply

  2. 0 Votes Thumb up 0 Votes Thumb down 0 Votes

    If heat were to be lost to some of the already melted water in the process, then the formula should have been… heat lost by copper = heat gained by ice + heat gained by water

    Admin - Mar 25, 2022 | Reply

  3. 0 Votes Thumb up 0 Votes Thumb down 0 Votes

    In reality, even the calorimeter/container will acquire some of the heat. In that case, the formula will be: heat lost by copper = heat gained by ice + heat gained by water + heat gained by container/calorimeter.

    Admin - Mar 25, 2022 | Reply


Answer Question