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# Find a positive value of p if the expression 2x² – px + p leaves a…

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**Find a positive value of p if the expression 2x² – px + p leaves a remainder 6 when divided by x – p**

**A.**** ****4**

**B.**** 3**

**C.**** ****2**

**D.**** ****1**

**QUICK ANSWER…**

**C**

**DETAILS…**

**Pay close attention and follow these steps to resolve questions like this.**

**Equate the divisor to zero, and make x the subject of the formula like this: x – p = 0, x = p****Substitute x for p in the main expression like this: 2x² – px + p = 2(p)² – p(p) + p = 2p² – p² + p = p² + p****Finally, equate the answer to the remainder like this: p² + p = 6**

**Solving this, we have:**

**p****²**** + p = 6**

**p****²**** + p – 6 = 0**

**factorizing, we have:**

**p****²**** – 2p + 3p – 6 = 0**

**(p****²**** – 2p) + (3p – 6) = 0**

**p(p – 2) + 3(p – 2) = 0**

**(p – 2)(p + 3) = 0**

**Therefore,**

**P – 2 = 0, p = 2**

**Or p + 3 = 0, p = -3**

**So, p = 2 or -3**

**Taking the positive value as required by the question, we have p = 2**

**Now for the right answer to the above question:**

**Option A is incorrect.****Option B is incorrect.****C is correct.****D is not the correct answer.**

**KEY-POINTS…**

**You may please note these/this:**

**The steps are clear…****Firstly, make x the subject of the divisor.****Secondly, substitute x for p into the original expression.****Thirdly, we will be left with an equation containing only p, then solve to find p.****Take the positive value of p as the required answer.****If you love our answers, you can login to comment and say hi to us at the comment section…**

**To raise new related question****s, c****lick the ASK A QUESTION BOTTON down this page…**

**/ culled from 2020 JAMB-UTME mathematics past question 33 /**

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