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**Find the value of x in the figure above**

**A. 20√3****B. 4√3****C. 5√3****D. 10√3**

**QUICK ANSWER…**

**D**

**SOLUTION****… **** **

**If two of the angles of the triangle are 30 and 60 degrees, then the remaining angle is obviously 90****ᵒ**

**This means we are free to use SOHCAHTOA to find x.**

**Tan ****θ = opposite/adjacent**

**Tan 60 = x/10**

**But tan 60 = ****√3**

**Therefore,**

**√3**** = x/10**

**10****√3**** = x**

**Now for the right answer to the above question:**

**Option A is incorrect.****Option B is incorrect.****C is incorrect.****D is the correct answer.**

**KEY-POINTS…**

**You may please note the****se/this****:**

**SOHCAHTOA is never to be applied to any triangle which has none of its angle as 90 degree.****Angles with a 90 degree is often called right angled triangle.****Again, only right-angled triangle is qualified to be resolved with SOHCAHTOA.****Any triangle which has none of its angles as 90 degree should be analyzed with sine or cosine rule.**

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**/ culled from 2015 JAMB-UTME mathematics past question 5 /**