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**In a class of 50 students, every student must offer at least one subject. 40 students offered physics and 30 offered biology. How many offered both physics and biology?**

- A.
**70** - B.
**20** - C.
**42** - D.
**54**

**QUICK ANSWER…**

**B**

**SOLUTION****… **** **

**If the number of students that offered both is x,**

**Then the number that offered physics alone = 40 – x**

**And the number that offered biology alone = 30 – x**

**Solving for x, we have:**

**(40 – x) + (x) + (30 – x) = 50**

**40 – x + x + 30 – x = 50**

**70 – x = 50**

**70 – 50 = x**

**20 = x**

**x = 20**

**Hence, the number of students that offered both physics and biology is 20.**

**Now for the right answer to the above question:**

**Option A is incorrect.****Option B is correct.****C is incorrect.****D is not the correct answer.**

**QUICK TIPS…**

**You may please note the****se/this****:**

**When resolving a problem with Venn diagram, ensure you take care of the middle first, and then subtract this middle from subsequent values as shown above.**

**Use the questions and answer session to correct, express, and contribute your views.**

**/culled from 2019 JAMB-UTME mathematics question 5 /**

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