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In how many ways can 2 students be selected from a group of 5 students in a debating competition?
A. 25 ways
B. 10 ways
C. 15 ways
D. 20 ways
QUICK ANSWER…
B
DETAILS…
The number of ways in which 2 students can be selected from a group of 5 students in a debating competition is 10.
Recall that:
rearrangement = permutation, while
selection = combination.
2 students can be selected from 5 students in ⁵C₂ = 10 ways
Now for the right answer to the above question:
- Option A is incorrect.
- Option B is correct.
- C is not correct.
- D is not the correct answer.
KEY-POINTS…
You may please note these/this:
In mathematical permutation and combination topics,
- Selection = combination.
- Rearrangement = permutation.
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/ culled from 2021 JAMB-UTME MATHEMATICS question 2 /