**In the above diagram MN is perpendicular to ON and MP. What is the difference between the moment about N of the force of 20 Newtons applied along MP and its moment about O?**

**A. zero**

**B. 0.2N.m**

**C. 0.4N.m**

**D. 0.8N.m**

**QUICK ANSWER…**

**A**

**DETAILS…**** **** **

**Recall, moment = force x perpendicular distance**

**If a force of 20N is applied along MP, then:**

**Moment of this force about N = 20 x MN**

**Now, using Pythagoras theorem to find MN, we have:**

**Moment about O = 20N x 0.4 = 8N.m**

**Hence, the difference between the two moments will be = 8 – 8 = 0**

**Now for the right answer to the above question:**

**A is the right answer. the both moments are the same.****B is incorrect.****C is incorrect.****D is incorrect.**

**KEY-POINTS…**

**You may please note this/these:**

**Moment = force x perpendicular distance.****For the both cases, the perpendicular distances of the force from N and O are the same.**

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**/ culled from 2020 JAMB-UTME physics past question 10 /**