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Tetraoxosulphate (vi) acid is prepared using the chemical reaction…

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Tetraoxosulphate (vi) acid is prepared using the chemical reaction

SO3(g) + H2O(s) H2SO4(l).

Given the heats of formation for SO3(g), H2O(l) and H2SO4(l) as -395KJmol-1, -286KJmol-1 and – 811KJmol-1 respectively, the enthalpy change accompanying this reaction is

  • A. -1032KJ
  • B. -130KJ
  • C. +130KJ
  • D. +1032KJ

QUICK ANSWER…

B

SOLUTION…  

Enthalpy change = heat of formation of product – heat of formation of reactants.

Heat of formation of product = heat of formation of sulphuric acid = – 811KJ/mol

Heat of formation of reactants = heat of formation of sulphur (vi) oxide + heat of formation of water = (-395) + (-286) = -395 – 286 = – 681KJ/mol

Hence, enthalpy change = (- 811) – (- 681) = – 811 + 681 = – 130 KJ/mol

Now for the right answer to the above question:

  1. Option A is incorrect.
  2. Option B is correct.
  3. C is incorrect.
  4. D is not the correct answer.

QUICK TIPS…

You may please note these/this:

  • Always remember, heat of reaction or enthalpy change = heat of formation of product(s) – heat of formation of reactant(s)

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/ culled from 2017 JAMB-UTME Chemistry question 3 /

Tetraoxosulphate (vi) acid is prepared using the chemical reaction... » QuizTablet
Tetraoxosulphate (vi) acid is prepared using the chemical reaction... » QuizTablet

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