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# The distance between two successive crests of a wave is 15 cm and…

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**The distance between two successive crests of a wave is 15 cm and the velocity is 300ms****¯¹. Calculate the frequency.**

**A. 4.5 × 10****⁵ Hz**

**B. 4.5 × 10² Hz**

**C. 2.0 × 10³ Hz**

**D. 2.0 × 10² Hz**

**QUICK ANSWER…**

**C**

**DETAILS…**

**The distance between two successive crests of a wave is actually its wavelength.**

**So, wavelength = 15cm = 15/100m = 0.15m**

**Velocity = ****300ms****¯¹**

**Now,**

**Now for the right answer to the above question:**

**Option A is incorrect.****Option B is incorrect.****C is correct.****D is not the correct answer. the number of zeros are three.**

**KEY-POINTS…**

**You may please note these/this:**

**Remember to convert the wavelength from cm to m, as the velocity is given in m/s.****The distance between two successive crests of a wave is = 1 wavelength.****The distance between two successive troughs of a wave is also = 1 wavelength.**

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**/ culled from 2015 JAMB-UTME physics past question 38 / **