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**The earth’s gravitational field intensity at its surface is about…**

**(G = 6.7 x 10 ^{-11}Nm^{2}kg^{-2}, mass of earth = 6 x 10^{24}kg, radius of the earth = 6.4 x 10^{6}m, g = ms^{-2} )**

- A.
**6.7N/kg** - B.
**7.9N/kg** - C.
**8.0N/kg** - D.
**9.8N/kg**

**QUICK ANSWER…**

**D**

**DETAILS…**

**The right formula for gravitational field intensity is given by:**

**Gravitational field intensity = force/mass**

**But according to Newton’s law of universal gravitation,**

**Now for the right answer to the above question:**

**Option A is incorrect.****Option B is incorrect.****C is incorrect.****D is the correct answer.**

**KEY-POINTS…**

**You may please note these/this:**

**Gravitational field intensity is equal to force/mass****Electric field intensity is similar, it equal to force/charge**

**Use the questions and answer section to correct, express, and contribute your views.**

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**/culled from 2019 JAMB-UTME physics question 34/**