# The gradient of a line which is perpendicular to the line with…

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**The gradient of a line which is perpendicular to the line with the equation 3x + 2y + 1 = 0**

- A.
**3/2**

- B.
**-3/2**

- C.
**2/3**

- D.
**-2/3**

**QUICK ANSWER…**

**C**

**SOLUTION****… **** **

**The general form of the equation of a straight line is like this:**

**y = mx + c**

**Where m = gradient or slope,**

**And c = intercept on y-axis.**

**Now for a line that is perpendicular (that cuts through the line at exactly 90 degrees) to the straight line represented by ****y = mx + c, the slope will not be m, but -1/m**

**Now to solve this problem, let us reduce ****3x + 2y + 1 = 0 to the form ****y = mx + c so that we can obtain m.**

**3x + 2y + 1 = 0**

**2y = -3x – 1**

**Dividing through by 2,**

**Now for the right answer to the above question:**

**Option A is incorrect.****Option B is incorrect.****C is correct.****D is not the correct answer.**

**QUICK TIPS…**

**You may please note the****se/this****:**

**If a line has a gradient of m, another line that is perpendicular to it will have a gradient of -1/m**

**Use the questions and answers session to raise further questions on this topic…**

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**/**** ****culled from ****201****8 ****JAMB-UTME ****mathematics ****question**** 32 ****/**

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