The gradient of a line which is perpendicular to the line with…
The gradient of a line which is perpendicular to the line with the equation 3x + 2y + 1 = 0
- A. 3/2
- B. -3/2
- C. 2/3
- D. -2/3
The general form of the equation of a straight line is like this:
y = mx + c
Where m = gradient or slope,
And c = intercept on y-axis.
Now for a line that is perpendicular (that cuts through the line at exactly 90 degrees) to the straight line represented by y = mx + c, the slope will not be m, but -1/m
Now to solve this problem, let us reduce 3x + 2y + 1 = 0 to the form y = mx + c so that we can obtain m.
3x + 2y + 1 = 0
2y = -3x – 1
Dividing through by 2,
Now for the right answer to the above question:
- Option A is incorrect.
- Option B is incorrect.
- C is correct.
- D is not the correct answer.
You may please note these/this:
- If a line has a gradient of m, another line that is perpendicular to it will have a gradient of -1/m
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/ culled from 2018 JAMB-UTME mathematics question 32 /
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