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# The pitch of a screw jack is 0.45cm…calculate the mechanical advantage.

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**The pitch of a screw jack is 0.45cm and the arm is 60cm long. If the efficiency of the jack is 75/****π %, calculate the mechanical advantage.**

- A.
**400** - B.
**300** - C.
**200** - D.
**150**

**QUICK ANSWER…**

**C**

**EXPLANATION…**

**Data given:**

**Pitch of screw jack = P = 0.45cm**

**The length of arm of the screw jack = L = 60cm**

**Efficiency = 75/****π**** %**

**Mechanical advantage = MA = ?**

**Now, we will use the popular formula which states:**

**Now for the right answer to the above question:**

**Option A is incorrect.****Option B is incorrect.****C is correct.****D is not the correct answer.**

**HELPFUL TIPS…**

**You may please note these/this:**

**The pitch of a screw jack is the height (or distance) through which a jack lifts its load after one complete circle of turning its arm by a mechanic.****If a mechanic completely turns a screw jack so that his arm forms one complete cycle, the height to which the load moves up is the pitch.****The distance travelled by effort will be the circular distance his arm moved to complete one circle. This is the circumference of the circle formed by his arm. We hope our explanation is clear enough.**

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**/culled from 2019 JAMB-UTME physics question 20/**