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The slope of the tangent to the curve y = 3×2 – 2x + 5 at…

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MATHS

The slope of the tangent to the curve y = 3×2 – 2x + 5 at the point (1, 6) is…

A. 1

B. 4

C. 5

D. 6

QUICK ANSWER…

B

SOLUTION 

The tangent of the curve at point (1, 6) is a straight line that cuts through that point. The slope of this straight line is what we are required to find.

Slope = dy/dx of the curve at point (1, 6)

The slope of the tangent to the curve y = 3x2 - 2x + 5 at the point (1, 6) is

The value of x at point (1, 6) = 1

Now substituting x = 1 into the differential, we have:

Slope = dy/dx = 6(1) – 2 = 6 – 2 = 4

Now for the right answer to the above question:

  1. Option A is incorrect.
  2. Option B is correct.
  3. C is incorrect.
  4. D is not the correct answer.

QUICK TIPS…

You may please note these/this:

  • Slope means the same thing as gradient or dy/dx, and can only be calculated on a straight line.

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/ culled from 2018 JAMB-UTME mathematics question 21 /

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