The slope of the tangent to the curve y = 3×2 – 2x + 5 at…
The slope of the tangent to the curve y = 3×2 – 2x + 5 at the point (1, 6) is…
The tangent of the curve at point (1, 6) is a straight line that cuts through that point. The slope of this straight line is what we are required to find.
Slope = dy/dx of the curve at point (1, 6)
The value of x at point (1, 6) = 1
Now substituting x = 1 into the differential, we have:
Slope = dy/dx = 6(1) – 2 = 6 – 2 = 4
Now for the right answer to the above question:
- Option A is incorrect.
- Option B is correct.
- C is incorrect.
- D is not the correct answer.
You may please note these/this:
- Slope means the same thing as gradient or dy/dx, and can only be calculated on a straight line.
Use the questions and answers session to deal further on this topic…
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/ culled from 2018 JAMB-UTME mathematics question 21 /