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What quantity of electricity will liberate 0.125 mole of oxygen…

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What quantity of electricity will liberate 0.125 mole of oxygen molecules during the electrolysis of dilute sodium chloride solution?

A. 24,125 C

B. 48,250 C

C. 72,375 C

D. 96,500 C

QUICK ANSWER…

A

DETAILS…

According to Faraday’s law of electrolysis,

  • For a mono-valent ion (eq: H, Cl¯, Na⁺, K⁺, F¯), 1 mole of its atom or molecule will be liberated by 96,500 coulombs of electricity.
  • For a di-valent ion (eq: Mg²⁺, O²¯, Ca²⁺), 1 mole of it will be liberated by 2 × 96500 = 193,000 coulombs of electricity.
  • For a tri-valent ion (eq: Al³), 1 mole of it will be liberated by 3 × 96500 = 289,500 coulombs of electricity.

To resolve this problem, oxygen is di-valent, it means:

1 mole of oxygen molecule = 193000C, therefore,

0.125 mole will be = X

Cross multiplying to find X, we have:

X(1) = 0.125 × 193000

X = 24,125 coulombs

Now for the right answer to the above question:

  1. Option A is correct.
  2. Option B is incorrect.
  3. C is incorrect.
  4. D is not the correct answer.
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KEY-POINTS…

You may please note these/this:

  • For a mono-valent ion, the quantity of electricity needed to liberate 1 mole of its product = 96500C
  • For a di-valent ion, the quantity of electricity needed to liberate 1 mole of its product = 2 × 96500 = 193000C
  • For a trivalent ion like aluminum ion, the quantity of electricity required to liberate 1 mole of its product will be = 3 × 96500C = 289500C
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/ culled from 2020 JAMB-UTME chemistry past question 27 /

What quantity of electricity will liberate 0.125 mole of oxygen... » QuizTablet
What quantity of electricity will liberate 0.125 mole of oxygen... » QuizTablet

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