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What quantity of electricity will liberate 0.125 mole of oxygen…
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What quantity of electricity will liberate 0.125 mole of oxygen molecules during the electrolysis of dilute sodium chloride solution?
A. 24,125 C
B. 48,250 C
C. 72,375 C
D. 96,500 C
QUICK ANSWER…
A
DETAILS…
According to Faraday’s law of electrolysis,
- For a mono-valent ion (eq: H⁺, Cl¯, Na⁺, K⁺, F¯), 1 mole of its atom or molecule will be liberated by 96,500 coulombs of electricity.
- For a di-valent ion (eq: Mg²⁺, O²¯, Ca²⁺), 1 mole of it will be liberated by 2 × 96500 = 193,000 coulombs of electricity.
- For a tri-valent ion (eq: Al³⁺), 1 mole of it will be liberated by 3 × 96500 = 289,500 coulombs of electricity.
To resolve this problem, oxygen is di-valent, it means:
1 mole of oxygen molecule = 193000C, therefore,
0.125 mole will be = X
Cross multiplying to find X, we have:
X(1) = 0.125 × 193000
X = 24,125 coulombs
Now for the right answer to the above question:
- Option A is correct.
- Option B is incorrect.
- C is incorrect.
- D is not the correct answer.
KEY-POINTS…
You may please note these/this:
- For a mono-valent ion, the quantity of electricity needed to liberate 1 mole of its product = 96500C
- For a di-valent ion, the quantity of electricity needed to liberate 1 mole of its product = 2 × 96500 = 193000C
- For a trivalent ion like aluminum ion, the quantity of electricity required to liberate 1 mole of its product will be = 3 × 96500C = 289500C
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/ culled from 2020 JAMB-UTME chemistry past question 27 /
