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When at equilibrium, which of the reactions below will shift to…

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When at equilibrium, which of the reactions below will shift to the right if the pressure is increased and the temperature is kept constant?

When at equilibrium, which of the reactions below will shift to the right if the pressure is increased and the temperature is kept constant?

QUICK ANSWER…

C

DETAILS…

The effect of change in pressure on the equilibrium position of a reversible chemical reaction depends on the total number of moles of GASES on the left-hand and right-hand side.

Equilibrium position always moves to the side with lesser number of moles of gas(es) when pressure is increased.

If the total number of moles of gases on the right-hand side is greater than the total number of moles of gasses on the left-hand side, the equilibrium position will move to the left at increased pressure.

If the total number of moles of gases on the left-hand side is greater than the total number of moles of gasses on the right-hand side, the equilibrium position will move to the right at increased pressure.

Now for the right answer to the above question:

  1. Option A is incorrect. the total number of moles of gas on the left is 2, while that on the right is 3. Equilibrium position will move to the left at increase in pressure.
  2. Option B is incorrect. the total number of moles of gas on the left is also 2, while that on the right is also 3. Equilibrium position will move to the left at increase in pressure.
  3. C is correct. the total number of moles of gas on the left is 3, while that on the right is 2. Equilibrium position will move to the right at increase in pressure.
  4. D is not the correct answer. The total number of moles of gases on both sides are equal, change in pressure will have zero effect on the equilibrium position.

KEY-POINTS…

You may please note these/this:

  • Please note that change in pressure only affects gasses and not aqueous neither liquid nor solid.
  • The number of moles of solid, liquid, or aqueous compounds are not counted, only gasses.
  • When pressure is increased, the reaction of the side with higher number of moles of gasses will be favored, pushing the equilibrium position to the side with lesser number of moles of gas(es).
  • Equilibrium position always moves to the side with lesser number of moles of gas(es) when pressure is increased.
  • And always moves to the side with higher number of moles of gas(es) when pressure is decreased.

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/ culled from 2015 JAMB-UTME Chemistry past question 26 /

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