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Which of the following will increase the yield of R?

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CHEMISTRY

P(g) + Q(g) ⇋ 3R(s) + S(g) ∆H is negative.

Which of the following will increase the yield of R?

A. using a larger closed vessel?

B. increasing the temperature.

C. Removing some S

D. Adding a positive catalyst

QUICK ANSWER…

C

SOLUTION…  

When faced with this kind of question, there are important points to note:

  • A total of two moles of gas can be seen on the reactants side.
  • One mole of gas can be seen on the product side.
  • Enthalpy change is negative, and
  • It is a reversible reaction.

Now for the right answer to the above question:

  1. Option A is incorrect. using a larger vessel simply mean subjecting the reaction to a reduced pressure. Now increase in pressure favors the side with more number of moles of gas (which in this case is the reactants), while reduction in pressure favors the side with the less number of moles of gas (which in this case is the product). So, using a larger vessel will favor the reverse reaction, that is, it will cause more of P and Q to be formed.
  2. Option B is incorrect. since enthalpy changer is negative, increasing the temperature will favor the reverse reaction, that is, more of P ands Q will be formed.
  3. C is correct. Simply removing the forming S will cripple the reverse reaction, this is because S is needed for the reverse reaction to proceed.
  4. D is not the correct answer. Addition of catalysts does not favor a particular side over the other, it only hastens the rate at which equilibrium is attained.
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QUICK TIPS…

You may please note these/this:

  • Removal of any component of a reversible reaction ensures that its participation in forming the reverse product is stopped.

Use the questions and answers session to raise further questions and deal more on this topic…

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/ culled from 2017 JAMB-UTME Chemistry question 15 /

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